How to use feedparpser to gain all RSS contents?

[seraphcj at gmail.com]

When using feedparpser object as below, it only contains 25 items, how can i have all contents?
for example,
d= feedparser.parse('http://newyork.craigslist.org/stp/index.rss')
print(len(d['entries'][i]['summary']))

result is 25....