list of the lists - append after search

[Andrew Zyman]

On Thursday, March 2, 2017 at 11:27:34 AM UTC-5, Peter Otten wrote:
> Andrew Zyman wrote:
> .....
> .....
> > End result:
> >  ll =[ [a,1], [b,2], [c,3], [blah, 1000, 'new value'] ]
> 
> >>> outer = [["a", 1], ["b", 2], ["c", 3], ["blah", 1000]]
> >>> for inner in outer:
> ...     if inner[0] == "blah":
> ...         inner.append("new value")

thank you. this will do. 
Just curious, is the above loop can be done in a one-liner?


> While this is what you are asking for it will get slower as the list grows. 
> A better solution uses a dictionary:

> >>> lookup = {inner[0]: inner[1:] for inner in outer}

Yes, understood, i don't expect the list to grow above a few thousand entries. But i do agree that utilizing the dict is more efficient.