how to group by function if one of the group has relationship with another one in the group?

[Ho Yeung Lee]

actually i used in this application
if same color is neighbor like connected then group them

i use for segmentation of words in screen capture

https://stackoverflow.com/questions/45294829/how-to-group-by-function-if-any-one-of-the-group-members-has-neighbor-relationsh

i asked here too, but i do not know how to use partial and do not know what center is.



On Wednesday, July 26, 2017 at 2:06:08 PM UTC+8, ast wrote:
> "Ho Yeung Lee" <jobmattcon at gmail.com> a écrit dans le message de 
> news:ef0bd11a-bf55-42a2-b016-d93f3b831860 at googlegroups.com...
> > from itertools import groupby
> >
> > testing1 = [(1,1),(2,3),(2,4),(3,5),(3,6),(4,6)]
> > def isneighborlocation(lo1, lo2):
> >    if abs(lo1[0] - lo2[0]) == 1  or lo1[1] == lo2[1]:
> >        return 1
> >    elif abs(lo1[1] - lo2[1]) == 1  or lo1[0] == lo2[0]:
> >        return 1
> >    else:
> >        return 0
> >
> > groupda = groupby(testing1, isneighborlocation)
> > for key, group1 in groupda:
> >    print key
> >    for thing in group1:
> >        print thing
> >
> > expect output 3 group
> > group1 [(1,1)]
> > group2 [(2,3),(2,4]
> > group3 [(3,5),(3,6),(4,6)]
> 
> Its not clear to me how you build the groups
> 
> Why (1,1) is not in group2 since (1,1) is
> a neighbor to both (2,3) and (2,4) ?