how to make this situation return this result?

[Thomas Jollans]

On 01/07/17 19:00, Lee Ho Yeung wrote:
> My situation is a dictionary with tuple key
> I think dictionary.values()[index]
> Is correct

Unless your dictionary only has one element, this is almost certainly
incorrect as dictionary items are not ordered: if this returns the right
object, then it's by sheer luck. This could return something else on a
different computer, or a different version of Python.

In Python 3, you can't even do this. (By the way, you should be using
Python 3!)

Normally when you want to access a particular item of a dictionary you
want to be indexing the dictionary itself: dictionary[key]

-- Thomas

>
>
> On Sun, 2 Jul 2017 at 12:48 AM, Pavol Lisy <pavol.lisy at gmail.com> wrote:
>
>> On 7/1/17, Ho Yeung Lee <jobmattcon at gmail.com> wrote:
>>> just want to compare tuples like index (0,1), (0,2), (1,2) without
>>> duplicate
>>>  such as (2,0), (1,0) etc
>>>
>>>
>>> On Saturday, July 1, 2017 at 7:00:17 PM UTC+8, Peter Otten wrote:
>>>> Ho Yeung Lee wrote:
>>>>
>>>>> finally i searched dict.values()[index] solved this
>>>> That doesn't look like a good solution to anything -- including "this",
>>>> whatever it may be ;)
>>>>
>>>> If you make an effort to better explain your problem in plain english
>>>> rather
>>>> than with code examples you are likely tho get better answers.
>>> --
>>> https://mail.python.org/mailman/listinfo/python-list
>>>
>> [(i, j) for j in range(3) for i in range(j)]  # is this good for you?
>>