smtplib TimeoutError not catch

[Joaquin Alzola]

>Not surprisingly, the exception you should catch is simply TimeoutError:

 >    try:
 >        server.sendmail(sender, receivers, msg.as_string())
 >    except TimeoutError as e:
 >        print("SMTP could not be contacted: %s" % e)
 >    finally:
 >       server.quit()

The error was thrown by another line :S, after putting the TimeoutError it work OK (with the proper exception line).

I had to apply a WA server = None to avoid the finally " UnboundLocalError: local variable 'server' referenced before assignment "

server = None
       try:
                server = smtplib.SMTP('smtp.mail.com')   <--- this is where the exception was happening.
                server.set_debuglevel(True) # show communication with the server
                server.sendmail(sender, receivers, msg.as_string())
        except TimeoutError as e:
                print("SMTP could not be access: %s"%e)
                pass
        finally:
                if server:
                        server.quit()


Joaquin
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