Why lambda in loop requires default?

[Terry Reedy]

On 3/26/2016 9:46 PM, gvim wrote:
> Given that Python, like Ruby, is an object-oriented language why doesn't
> this:
>
> def m():
>    a = []
>    for i in range(3): a.append(lambda: i)
>    return a
>
>def echo_i: return i

> b = m()
> for n in range(3): print(b[n]())  # =>  2  2  2

)  # =>  2  2  2
>
> ... work the same as this in Ruby:
>
> def m
>    a = []
>    (0..2).each {|i| a << ->(){i}}
>    a
> end
>
> aa = m
> (0..2).each {|n| puts aa[n].()}  # =>  0  1  2

Since Python came first, and Ruby was partly inspired by and derived 
from Python, perhaps you should ask Ruby folk why it does not work the 
same as Python.  (Because Matz wanted it different.)

> lambda i=i: i
>
> ... is needed to make it work in Python. Just wondered why?

Your Python def m is essentially equivalent to

def m():
   def echo_i(): return i
   i = 2
   return [echo_i]*3

-- 
Terry Jan Reedy