Understanding " 'xml.etree.ElementTree.Element' does not support the buffer interface"
Saran Ahluwalia
ahlusar.ahluwalia at gmail.com
Mon Jan 11 16:54:48 EST 2016
Hi Steven:
Just as an update - apparently there were bytes in the Windows Command
Terminal that were interrupting the process execution. I didn't realize
this was happening until I dug around Windows' Q&A forum.
Cheers
On Sun, Jan 10, 2016 at 12:53 PM, Saran Ahluwalia <
ahlusar.ahluwalia at gmail.com> wrote:
> Hi Steven:
>
> The previous code was a stand along under the " if __name__ ==
> '__main__': ". The full function suite that I have made (and indeed
> includes a try and except block):
>
> import os.path
> import sys
> import csv
> from io import StringIO
> import xml.etree.cElementTree as ElementTree
> from xml.etree.ElementTree import XMLParser
> # import xml
> # import xml.sax
> # from xml.sax import ContentHandler
>
>
> def flatten_list(self, aList, prefix=''):
>
> for i, element in enumerate(aList, 1):
> eprefix = "{}{}".format(prefix, i)
> if element:
> # treat like dict
> if len(element) == 1 or element[0].tag != element[1].tag:
> yield from flatten_dict(element, eprefix)
> # treat like list
> elif element[0].tag == element[1].tag:
> yield from flatten_list(element, eprefix)
> elif element.text:
> text = element.text.strip()
> if text:
> yield eprefix[:].rstrip('.'), element.text
>
>
> def flatten_dict(parent_element, prefix=''):
>
> prefix = prefix + parent_element.tag
> if parent_element.items():
> for k, v in parent_element.items():
> yield prefix + k, v
> for element in parent_element:
> eprefix = element.tag
> if element:
> # treat like dict - we assume that if the first two tags
> # in a series are different, then they are all different.
> if len(element) == 1 or element[0].tag != element[1].tag:
> yield from flatten_dict(element, prefix=prefix)
> # treat like list - we assume that if the first two tags
> # in a series are the same, then the rest are the same.
> else:
> # here, we put the list in dictionary; the key is the
> # tag name the list elements all share in common, and
> # the value is the list itself
> yield from flatten_list(element, prefix=eprefix)
> # if the tag has attributes, add those to the dict
> if element.items():
> for k, v in element.items():
> yield eprefix+k
> # this assumes that if you've got an attribute in a tag,
> # you won't be having any text. This may or may not be a
> # good idea -- time will tell. It works for the way we are
> # currently doing XML configuration files...
> elif element.items():
> for k, v in element.items():
> yield eprefix+k
> # finally, if there are no child tags and no attributes, extract
> # the text
> else:
> yield eprefix, element.text
>
>
>
> def just_xml_data(path):
> with open(path, 'rU', encoding='UTF-8') as data:
> separated = data.read().split('","')
> print(separated)
> try:
> x = ElementTree.XML(separated[3])
> print(x)
> xml.etree.ElementTree.dump(x)
> y = ElementTree.XML(separated[4])
> xml.etree.ElementTree.dump(y)
> # response = ElementTree.XML(separated[4]) # work on the
> Response column
> # root = ElementTree.XML(response) #serialize and parse into
> XML object
> except Exception as e:
> print(e)
> else:
> xml_field = dict(flatten_dict(y))
> return xml_field
>
> def read_data(path):
> headers= set()
> rows = []
> with open(path, 'rU', encoding='utf-8') as data:
> reader = csv.DictReader(data, dialect=csv.excel,
> skipinitialspace=True)
> for row in reader:
> xml_field = row["CLIENT_RESP_DATA"]
> # xml_data = just_xml_data(xml_field) ## function
> if xml_data is not None:
> row.update(xml_data)
> headers.update(row.keys())
> rows.append(row)
> else:
> print("Failure")
> pass
> with open(os.path.splitext(textFile)[0] + '_' + 'parsed' + '.csv',
> "wt", newline='') as output_file:
> wr = csv.writer(output_file)
> csv_headers = list(headers)
> wr.writerow(csv_headers)
> for row in rows:
> values = []
> for field in csv_headers:
> value = row.get(field, None)
> values.append(value)
> wr.writerow(values)
> return output_file
>
>
>
> if __name__ == '__main__':
> Response = "s.csv"
> just_xml_data(Response)
>
>
> Hopefully this will provide you with enough information to emulate
> (apologies for any and all indentation errors during the copy and paste).
> FYI - I still receive the same error.
>
>
> On Sun, Jan 10, 2016 at 12:27 PM, Steven D'Aprano <steve at pearwood.info>
> wrote:
>
>> On Mon, 11 Jan 2016 02:04 am, kbtyo wrote:
>>
>> > Hello Everyone:
>> >
>> > I am curious to know why I receive the aforementioned message. I am
>> using
>> > Python 3.4.3 and Windows 7. I am running the following script from
>> Windows
>> > Powershell:
>>
>> I created a file "data" containing the input data you said:
>>
>> > The input data is as follows:
>> >
>> > A,B,C,D,E,F,G,H,I,J
>> > "3","8","1","<Request TransactionID="3"
>> RequestType="FOO"><InstitutionISO
>> > /><CallID>23</CallID><MemberID>12</MemberID><MemberPassword
>> >
>> /><RequestData><AccountNumber>2</AccountNumber><AccountSuffix>85</AccountSuffix><AccountType>S</AccountType><MPIAcctType>Checking</MPIAcctType><TransactionCount>10</TransactionCount></RequestData></Request>","<Response
>> > TransactionID="2"
>> >
>>
>> RequestType="HoldInquiry"><PulledLoans>True</PulledLoans><PulledClosedLoans>False</PulledClosedLoans><PulledInvestments>False</PulledInvestments><PulledClosedInvestments>False</PulledClosedInvestments><PulledCards>False</PulledCards><ShareList>0000',0001,0070,</ShareList></Response>","1967-12-25
>> > 22:18:13.471000","2005-12-25 22:18:13.768000","2","70","0"
>>
>>
>>
>> and then a script containing the code you said you used:
>>
>> > import xml.etree.cElementTree as ElementTree
>> > from xml.etree.ElementTree import XMLParser
>>
>> > Response = 's.csv'
>> > with open(Response, 'rU', encoding='utf-8') as data:
>> > separated = data.read().split('","')
>> > x = ElementTree.XML(separated[3])
>> > y = ElementTree.XML(separated[4])
>> > print(dict(flatten_dict(x)))
>> > print(dict(flatten_dict(y)))
>>
>>
>> I get a completely different error to you, complete with traceback as
>> expected:
>>
>> Traceback (most recent call last):
>> File "/tmp/testxml.py", line 9, in <module>
>> print(dict(flatten_dict(x)))
>> NameError: name 'flatten_dict' is not defined
>>
>>
>> This shows me three things:
>>
>> (1) The calls to ElementTree.XML work fine, and don't raise an exception;
>>
>> (2) There is no error message referring to xml.etree.ElementTree.Element
>> or
>> the buffer interface;
>>
>> (3) The code you posted is clearly not the code you actually ran. At the
>> very least, it is not *all* the code you ran.
>>
>> We cannot tell what it wrong with your code if you don't show us the code
>> that fails. I suggest you read this webpage:
>>
>> http://www.sscce.org/
>>
>> and follow the advice given. It's written for Java, but applies to any
>> programming language. Hopefully you will either solve your problem, or be
>> able to generate a sufficiently small piece of code that we can work with.
>>
>>
>> You also suggest that your code works when running in a Jupyter Notebook.
>> It
>> is unlikely (but not impossible!) that exactly the same code will run
>> differently when run as a script and when run under Jupyter. More likely,
>> there is some difference between the code, something you have written in
>> the Notebook but not included in the script.
>>
>> If it is exactly the same code, then perhaps it is a difference in the two
>> environments. Does Jupyter set up the environment differently to what you
>> get when running a script?
>>
>> Finally, in another post, you state:
>>
>> "That is the only message (*xml.etree.ElementTree.Element' does not
>> support
>> the buffer interface"*). There is no traceback."
>>
>>
>> That is very unlikely with the code sample you posted. If true, that gives
>> more evidence that you are running code which is different from what you
>> have posted here. Perhaps your ACTUAL code (not the pretend code you
>> showed
>> us) includes a try...except block like this:
>>
>> try:
>> some code goes here
>> except Exception as err:
>> print(err)
>> sys.exit()
>>
>>
>> or similar. If so, TAKE IT OUT. That is destroying useful debugging
>> information and making it more difficult to solve your problem.
>>
>>
>>
>>
>>
>> --
>> Steven
>>
>> --
>> https://mail.python.org/mailman/listinfo/python-list
>>
>
>
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