Finding the first index in a list greater than a particular value

[Atri Mahapatra]

On Monday, 15 August 2016 00:03:59 UTC+5:30, MRAB  wrote:
> On 2016-08-14 19:17, Atri Mahapatra wrote:
> > I have a list of dictionaries which look like this:
> > [{'Width': 100, 'Length': 20.0, 'Object': 'Object1'}, {'Width': 12.0, 'Length': 40.0, 'Object': 'Object2'}...... so on till 10]
> >
> > I would like to find the first index in the list of dictionaries whose length is greater than a particular value
> >
> > f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii]['Length'] > m][0] and it throws an error
> >
> > can  anyone suggest a way  to do it?
> >
> What is the error?

Traceback (most recent call last):
  File "<pyshell#12>", line 1, in <module>
    f(lengthlist, 10)
   f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii] > m][0]
TypeError: unorderable types: dict() > int()