Serious error in int() function?

[ast]

<martin.spichty at gmail.com> a écrit dans le message de 
news:52f7516c-8601-4252-ab16-bc30c59c8306 at googlegroups.com...
> Hi,
>
> there may be a serious error in python's int() function:
>
> print int(float(2.8/0.1))
>
> yields
>
> 27
>
> instead of 28!!
>
> I am using Python Python 2.7.6, GCC 4.8.2 on Linux Ubuntu.
>
> Is that known?
> Best,
> Martin


I have a similar question, so I post my message here.
Hope this will not annoy the OP


Is it sure that the square root of a square number is always
an integer ?

I would not like to get a result as 345.99999999

from math import sqrt

>>>sqrt(16)
4.0
>>> sqrt(16).is_integer()
True

>>> for n in range(1000000):
...         if not sqrt(n**2).is_integer():
...             print(sqrt(n**2))

it seems to work ... but does it work for all integers ?