Joining Strings

[Emeka]

Jussi,

Thanks it worked when parsed with json.load. However, it needed this
decode('utf'):

data = json.loads(respData.decode('utf-8'))

On Thu, Apr 7, 2016 at 6:01 AM, Jussi Piitulainen <
jussi.piitulainen at helsinki.fi> wrote:

> Emeka writes:
>
> > Hello All,
> >
> > import urllib.request
> > import re
> >
> > url = 'https://www.everyday.com/
> >
> >
> >
> > req = urllib.request.Request(url)
> > resp = urllib.request.urlopen(req)
> > respData = resp.read()
> >
> >
> > paragraphs = re.findall(r'\[(.*?)\]',str(respData))
> > for eachP in paragraphs:
> >     print("".join(eachP.split(',')[1:-2]))
> >     print("\n")
> >
> >
> >
> > I got the below:
> > "Coke -  Yala Market Branch""NO. 113 IKU BAKR WAY YALA"""
> > But what I need is
> >
> > 'Coke -  Yala Market Branch NO. 113 IKU BAKR WAY YALA'
> >
> > How to I achieve the above?
>
> A couple of things you could do to understand your problem and work
> around it: Change your code to print(eachP). Change your "".join to
> "!".join to see where the commas were. Experiment with data of that form
> in the REPL. Sometimes it's good to print repr(datum) instead of datum,
> though not in this case.
>
> But are you trying to extract and parse paragraphs from a JSON response?
> Do not use regex for that at all. Use json.load or json.loads to parse
> it properly, and access the relevant data by indexing:
>
> x = json.loads('{"foo":[["Weather Forecast","It\'s Rain"],[]]}')
>
> x ==> {'foo': [['Weather Forecast', "It's Rain"], []]}
>
> x['foo'] ==> [['Weather Forecast', "It's Rain"], []]
>
> x['foo'][0] ==> ['Weather Forecast', "It's Rain"]
> --
> https://mail.python.org/mailman/listinfo/python-list
>



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