Screen scraper to get all 'a title' elements

[ryguy7272]

On Wednesday, November 25, 2015 at 3:42:21 PM UTC-5, ryguy7272 wrote:
> Hello experts.  I'm looking at this url:
> https://en.wikipedia.org/wiki/Wikipedia:Unusual_place_names
> 
> I'm trying to figure out how to list all 'a title' elements.  For instance, I see the following:
> <a title="Accident, Maryland" href="/wiki/Accident,_Maryland">Accident</a>
> <a class="new" title="Ala-Lemu (page does not exist)" href="/w/index.php?title=Ala-Lemu&action=edit&redlink=1">Ala-Lemu</a>
> <a title="Alert, Nunavut" href="/wiki/Alert,_Nunavut">Alert</a>
> <a title="Apocalypse Peaks" href="/wiki/Apocalypse_Peaks">Apocalypse Peaks</a>
> 
> So, I tried putting a script together to get 'title'.  Here's my attempt.
> 
> import requests
> import sys
> from bs4 import BeautifulSoup
> 
> url = "https://en.wikipedia.org/wiki/Wikipedia:Unusual_place_names"     
> source_code = requests.get(url) 
> plain_text = source_code.text
> soup = BeautifulSoup(plain_text)
> for link in soup.findAll('title'):
>     print(link)
> 
> All that does is get the title of the page.  I tried to get the links from that url, with this script.
> 
> import urllib2
> import re
> 
> #connect to a URL
> website = urllib2.urlopen('https://en.wikipedia.org/wiki/Wikipedia:Unusual_place_names')
> 
> #read html code
> html = website.read()
> 
> #use re.findall to get all the links
> links = re.findall('"((http|ftp)s?://.*?)"', html)
> 
> print links
> 
> That doesn't work wither.  Basically, I'd like to see this.
> 
> Accident
> Ala-Lemu
> Alert
> Apocalypse Peaks
> Athol
> Å
> Barbecue
> Båstad
> Bastardstown
> Batman
> Bathmen (Battem), Netherlands
> ...
> Worms
> Yell
> Zigzag
> Zzyzx
> 
> How can I do that?
> Thanks all!!



Ok, I guess that makes sense.  So, I just tried the script below, and got nothing...

import requests
from bs4 import BeautifulSoup

r = requests.get("https://en.wikipedia.org/wiki/Wikipedia:Unusual_place_names")
soup = BeautifulSoup(r.content)
print soup.find_all("a",{"title"})