What is wrong in this example code?

fl rxjwg98 at gmail.com
Thu Nov 12 09:07:45 EST 2015


On Thursday, November 12, 2015 at 8:58:33 AM UTC-5, fl wrote:
> Hi,
> 
> I run a code snippet from link:
> http://www.python-course.eu/inheritance_example.php
> 
> It is found that there is an error in this loop:
> 
> for i in xrange(10000):
>     x.tick()
> print(x)
> SyntaxError: invalid syntax
> 
> 
> I have modified it to:
> for i in x range(10000):
>     x.tick()
> print(x)
> SyntaxError: invalid syntax
> 
> it still has an error. What could be wrong?
> 
> Thanks,
> 
> 
> ....
> class Clock(object):
> 
>     def __init__(self,hours=0, minutes=0, seconds=0):
>         self.__hours = hours
>         self.__minutes = minutes
>         self.__seconds = seconds
> 
>     def set(self,hours, minutes, seconds=0):
>         self.__hours = hours
>         self.__minutes = minutes
>         self.__seconds = seconds
> 
>     def tick(self):
>         """ Time will be advanced by one second """
>         if self.__seconds == 59:
>             self.__seconds = 0
>             if (self.__minutes == 59):
>                 self.__minutes = 0
>                 self.__hours = 0 if self.__hours==23  else self.__hours+1
> 	    else:
> 		self.__minutes += 1;
> 	else:
>             self.__seconds += 1;
> 
>     def display(self):
>         print("%d:%d:%d" % (self.__hours, self.__minutes, self.__seconds))
> 
>     def __str__(self):
>         return "%2d:%2d:%2d" % (self.__hours, self.__minutes, self.__seconds)
> 
> x = Clock()
> print(x)
> for i in xrange(10000):
>     x.tick()
> print(x)

Solved it by this:
print(x)
for i in range(1, 10000):
         x.tick()
print(x)

Thanks,



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