Returning a custom file object (Python 3)
Ben Finney
ben+python at benfinney.id.au
Wed May 27 22:34:49 EDT 2015
Steven D'Aprano <steve at pearwood.info> writes:
> from io import TextIOWrapper
> class MyFile(TextIOWrapper):
> pass
>
> but how do I tell open() to use MyFile?
I haven't used it, but does the ‘opener’ parameter do what you want?
open(file, mode='r', buffering=-1, encoding=None,
errors=None, newline=None, closefd=True, opener=None) ->
file object
[…]
A custom opener can be used by passing a callable as *opener*. The
underlying file descriptor for the file object is then obtained by
calling *opener* with (*file*, *flags*). *opener* must return an
open file descriptor (passing os.open as *opener* results in
functionality similar to passing None).
--
\ “Our products just aren't engineered for security.” —Brian |
`\ Valentine, senior vice-president of Microsoft Windows |
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Ben Finney
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