Logging Custom Levels?

[Jean-Michel Pichavant]

----- Original Message -----
> From: "Didymus" <lynto28 at gmail.com>
> To: python-list at python.org
> Sent: Tuesday, 31 March, 2015 5:20:52 PM
> Subject: Logging Custom Levels?
> 
> Hi,
> 
> I've create a Python file called "log.py" and placed in the custom
> levels:
> 
> # Performance Debug...
> logging.addLevelName(PDEBUG_NUM, "PDEBUG")
> 
> def pdebug(self, message, *args, **kws):
>     """ Performance Debug Message Level """
>     self.log(PDEBUG_NUM, message, *args, **kws)
>         
> logging.Logger.pdebug = pdebug
> 
> 
> This works except that the %(module) and %(lineno) does not print
> properly, it instead prints out as the "log.py" and the line that
> this is on. I think I figured out a way to get the module and line
> from the calling custom level:
> 
> import inspect
> frame = inspect.currentframe()
> filename =
> os.path.splitext(os.path.basename(frame.f_back.f_code.co_filename))[0]
> linenumber = frame.f_back.f_lineno
> 
> 
> My question is how do I pass this into the "self.log" call properly?
> I've tried a few different things without any luck. Any ideas how I
> can pass this into the custom logging level and get it to work?
> 
> Thanks in Advance for any help!
>     Tom

A solution is pretty simple, do not use an intermediate log function pdebug.

import logging
PDEBUG_NUM=20
logging.addLevelName(PDEBUG_NUM, "PDEBUG")
 
logger = logging.getLogger('foo')
logging.basicConfig(level=logging.DEBUG, format='%(message)s %(lineno)d')

logger.log(PDEBUG_NUM, 'This will work :')


If you *really* want to go for the hackish way, forget about the inspect module, the following pdebug function should do the trick:

def pdebug(self, message, *args, **kws):
    if self.isEnabledFor(PDEBUG_NUM):
        self._log(PDEBUG_NUM, message, args, **kws)

Cheers,

JM


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