Supply condition in function call

[Cameron Simpson]

On 26Mar2015 11:37, Peter Otten <__peter__ at web.de> wrote:
>You are right. [...]
>
>By the way, in this case you don't need the list at all:
>
>def vartuple(vars):
>    return namedtuple("locals", vars)._make(vars.values())

Hmm. Neat. I had not realised that was available.

You'd need "vars.keys()", not "vars", for the first use of "vars", BTW:

  return namedtuple("locals", vars.keys())._make(vars.values())

A remark for the OP: a method name like "_make" would normally be something you 
would avoid as it is Python convenion that _* names are "private", which in 
Python usually means subject to arbitrary change and probably not documented; 
internal implementation mechanisms as opposed to published interfaces.

However, in namedtuple the word "_make" is chosen specificly to avoid clashes 
with the "named" tuple values (which would normally not start with "_"), and it 
is explicitly documented.

Thanks Peter!

Cheers,
Cameron Simpson <cs at zip.com.au>

Nothing is impossible for the man who doesn't have to do it.