Regex Python Help

[Gregg Dotoli]

This works fine , but I have to pipe the filename to the script python stool <foo

All I need is a loop, should I bag Python and use a simple shell for loop?


import sys
import re
import os
pattern="DECRYPT_I"
regexp=re.compile(pattern)
for line in sys.stdin:
    result=regexp.search(line)
    if result:
        sys.stdout.write(line)


































On Tuesday, March 24, 2015 at 2:14:32 PM UTC-4, Gregg Dotoli wrote:
> I am creating a tool to search a filesystem for one simple string.
> I cannot get the syntax correct.
> Thank you in advance for your help.
> 
> import sys
> import re
> import os
> path='/'
> viewfiles=os.listdir(path)
> for allfiles in viewfiles:
>     file= os.path.join(path, allfiles)
> text=open(file, "r")
> for line in text:
>     if re.match("DECRYPT_I", line):
>         print line, 
> 
> ----------------------------------------------------------
> This should search every file for the simple regex "DECRYPT_I"
> This is from the root down.
> 
> The error is:
> 
> SyntaxError: Missing parentheses in call to 'print'
> 
> Please help.
> Gregg Dotoli