Is nan in (nan,) correct?

[Chris Angelico]

On Sat, Mar 7, 2015 at 4:04 AM, Rustom Mody <rustompmody at gmail.com> wrote:
> You dont grok your theory of computation very well do you?
>
> def foo(x): return x + x
> def bar(x): return x + x
> def baz(x): return 2*x
>
> One can imagine an implementation where
> id(foo) == id(bar)
> [I am assuming that id is a good enough approx to bit_representation]
>
> Can you imagine an implementation where
> id(bar) == id(baz)
> ?

No, I cannot imagine either. Those functions have different
identities. They may be considered *equal* but they should not be
*identical*. I can imagine a language in which they are considered
indistinguishable and optimized down to one, but if you consider them
to be the same function, then you've abolished all concept of
identity.

Also, I have no idea what any of this has to do with nans and
container membership.

ChrisA