Sort list of dictionaries

[Charles Heizer]

Hello,
I'm new to python and I'm trying to find the right way to solve this issue I have.

I'm trying to sort this list by name and then by version numbers. The problem I'm having is that I can not get the version numbers sorted with the highest at the top or sorted properly. 

mylist = [{'name': u'com.google.earth', 'version': u'7.1.2.2041'},
{'name': u'com.google.earth', 'version': u'7.1.2.2019'},
{'name': u'com.google.Chrome', 'version': u'40.0.2214.93'},
{'name': u'com.google.Chrome', 'version': u'40.0.2214.91'},
{'name': u'com.google.Chrome', 'version': u'40.0.2214.111'},
{'name': u'com.google.Chrome', 'version': u'39.0.2171.99'},
{'name': u'com.google.Chrome', 'version': u'39.0.2171.95'},
{'name': u'com.google.Chrome', 'version': u'39.0.2171.71'},
{'name': u'com.google.Chrome', 'version': u'38.0.2125.122'},
{'name': u'com.google.Chrome', 'version': u'38.0.2125.111'},
{'name': u'com.google.Chrome', 'version': u'38.0.2125.104'},
{'name': u'com.google.Chrome', 'version': u'38.0.2125.101'},
{'name': u'com.google.Chrome', 'version': u'37.0.2062.94'},
{'name': u'com.google.Chrome', 'version': u'37.0.2062.120'},
{'name': u'com.google.Chrome', 'version': u'36.0.1985.143'},
{'name': u'com.google.Chrome', 'version': u'36.0.1985.125'},
{'name': u'com.google.Chrome', 'version': u'35.0.1916.153'},
{'name': u'com.google.Chrome', 'version': u'35.0.1916.114'},
{'name': u'com.google.Chrome', 'version': u'34.0.1847.137'},
{'name': u'com.google.Chrome', 'version': u'34.0.1847.131'},
{'name': u'com.google.Chrome', 'version': u'34.0.1847.116'},
{'name': u'com.google.Chrome', 'version': u'33.0.1750.152'},
{'name': u'com.google.Chrome', 'version': u'33.0.1750.149'},
{'name': u'com.google.Chrome', 'version': u'33.0.1750.146'},
{'name': u'com.google.Chrome', 'version': u'32.0.1700.107'},
{'name': u'com.google.Chrome', 'version': u'31.0.1650.63'},
{'name': u'com.google.Chrome', 'version': u'31.0.1650.57'}]

sortedlist = sorted(mylist , key=lambda x, y: x['name'] LooseVersion(elem['version'])), reverse=True)

Thanks,
Charlie