Could you give me the detail process of 'make_incrementor(22)(33)'?

[fl]

Hi,

I read a tutorial on lambda on line. I don't think that I am clear about
the last line in its example code. It gives two parameters (22, 23). 
Is 22 for n, and 23 for x? Or, it creates two functions first. Then,
each function gets 22 while the other function gets 23?


Please help me on this interesting problem. Thanks,






>>> def make_incrementor (n): return lambda x: x + n
>>> 
>>> f = make_incrementor(2)
>>> g = make_incrementor(6)
>>> 
>>> print f(42), g(42)
44 48
>>> 
>>> print make_incrementor(22)(33)