"normalizing" a value

[bvdp]

On Wednesday, July 1, 2015 at 7:15:28 PM UTC-7, Steven D'Aprano wrote:
> On Thu, 2 Jul 2015 10:12 am, bvdp wrote:
> 
> > Not sure what this is called (and I'm sure it's not normalize). Perhaps
> > "scaling"?
> 
> 
> Could be normalising, could be scaling.
>  
> > Anyway, I need to convert various values ranging from around -50 to 50 to
> > an 0 to 12 range (this is part of a MIDI music program). I have a number
> > of places where I do:
> 
> You say "around" -50 to 50. Can you get 51? 151? How do you want to treat
> such out of range numbers?
> 
> Are the values integer valued, or can they include fractional values like
> 27.356?
> 
> >    while x < 0: x += 12
> >    while x >= 12: x -= 12
> > 
> > Okay, that works. Just wondering if there is an easier (or faster) way to
> > accomplish this.
> 
> 
> One approach is to just re-scale the numbers from the range -50...50 to
> 0...12 inclusive. That is:
> 
>     before => after
>     -50 => 0
>     0 => 6
>     50 => 12
> 
> 
> and everything in between is scaled equivalently. Given x between -50 and 50
> inclusive, calculate:
> 
>     y = (x+50)/100.0*12
> 
> 
> (Note that in Python 2, you need to make at least one of those values a
> float, otherwise you may get unexpected results.)
> 
> That will give you y values from the range 0.0 to 12.0 inclusive. If x is
> less than -50.0 or more than +50.0 y will likewise be out of range. You can
> clip the result:
> 
>     y = min(12.0, max(0.0, y))
> 
> If your x values are integer values (no fractional values) between -50 and
> +50 you can use clock arithmetic. Think of a clock marked 0 to 12 (so there
> are 13 values), once you reach 12 adding 1 takes you back to 0.
> 
>     0, 13, 26, 39 => 0
>     1, 14, 27, 40 => 1
>     2, 15, 28, 41 => 2
>     ...
>     12, 25, 38, 51 => 12
> 
> 
> Extending that to negative values in the most obvious fashion:
> 
>     -1, -14, -27, -40 => 12
>     ...
>     -12, -25, -38, -51 => 1
>     -13, -26, -39, -52 => 0
>     
> 
> We can do that easily with the % (modulo) operator:
> 
>     y = x % y
> 
> 
> Modulo even works with non-integer values:
> 
> py> 13.5 % 13
> 0.5
> 
> 
> 
> -- 
> Steven

Thanks for this Steven. However, I think it's not correct in this case. Like I said in another message X%12 is working just fine. No matter what the value is.