How to terminate the function that runs every n seconds

[Ganesh Pal]

I quick modified the code and it now looks like this ,is this ok for
termination ? I played with t.canel() it didn't work

import threading
import time
def printit():
        print "EXECUTED SLEEP"

t = threading.Timer(4, printit)
t.start()
printit()
print "hello"

output :

Throttling-1# python  file_02.py
EXECUTED SLEEP
hello
EXECUTED SLEEP



On Wed, Jan 14, 2015 at 6:39 PM, Ganesh Pal <ganesh1pal at gmail.com> wrote:
> Corrected Typos .
>
>>a) How to I prevent the execution  of   Print "EXECUTED SLEEP" after 4
>> seconds ? , current this is running in an infinite loop
>
>
> On Wed, Jan 14, 2015 at 6:37 PM, Ganesh Pal <ganesh1pal at gmail.com> wrote:
>> Iam using Linux and  Python 2.7  and playing with the threading.Timer module.
>>
>> I had the below question on the same.
>>
>> (a) How to I prevent the execution  the  "EXECUTED SLEEP" after 4
>> seconds ? , current this is running in an infinite loop
>>
>> node-1# cat  file_01.py
>>
>> import threading
>> import time
>> def printit():
>>         threading.Timer(2, printit).start()
>>         print "EXECUTED SLEEP"
>> printit()
>> print "hi"
>> time.sleep(4)
>> print "hi"
>> time.sleep(5)
>>
>> Output:
>> node-1# python  file_01.py
>> EXECUTED SLEEP
>> hi
>> EXECUTED SLEEP
>> EXECUTED SLEEP
>> EXECUTED SLEEP
>>
>>
>>
>> Regards,
>> Ganesh