Namespace puzzle, list comprehension fails within class definition

[Ethan Furman]

On 01/12/2015 12:25 PM, John Ladasky wrote:
> d = {0:"a", 1:"b", 2:"c", 3:"d"}
> e = [d[x] for x in (0,2)]
> 
> class Foo:
>     f = {0:"a", 1:"b", 2:"c", 3:"d"}
>     print(f)
>     g = [f[x] for x in (0,2)]

In Foo 'f' is part of an unnamed namespace; the list comp 'g' has its own namespace, effectively making be a nonlocal;
class name lookup skips nonlocal namespaces.

Workaround:  use an actual for loop.

--
~Ethan~

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