Why For Loop Skips the Last element?

Mark Lawrence breamoreboy at yahoo.co.uk
Thu Jan 1 04:28:06 EST 2015


On 31/12/2014 21:25, Thuruv V wrote:
> Hi all,
>
> Here's the list. .
>
> inlist = ["Fossil Women's Natalie Stainless Steel Watch Brown (JR1385)",
> 'Balmer Swiss Made Veyron Mens Watch: Black Band/ Black Dial (62625241)',
> 'Fortune NYC Ladies Quilted Dial Watch: Brown',
> 'Jeanne Collection w/ Swarovski Elements Watch: Dark Purple Band
> (62623659)',
> 'Swiss Legend Commander Chronograph: Watch Orange/Black (SL-10067-01-ORS)',
> 'Debussy Ladies Watch: Brown/Gray/Silver 14070 - 62625292',
> '#2 Swiss Legend Commander Chronograph: Green (SL-10067-BB-017)',
> 'Auguste Jaccard 3 Timezone Watch: Black Band/ Gray & Black Dial (62625184)'
> ]
>
> My code :
> i = 0
> while i <= len(inlist):
>      if 'watch' in str(inlist[i]).lower() or 'watches' in
> str(inlist[i]).lower():
>          if 'women' in str(inlist[i]).lower() or 'female' in
> str(inlist[i]).lower() or 'ladies' in str(inlist[i]).lower():
>              print 'FEMale Watch', inlist.index(i),str(i)
>          elif 'men' in str(inlist[i]).lower() or 'male' in
> str(inlist[i]).lower() or 'chronograph' in str(inlist[i]).lower():
>              print 'Male Watch',inlist.index(i),str(i)
>          i = next(inlist)
>
> When on executing python skips the last element('Auguste Jaccard 3
> Timezone Watch: Black Band/ Gray & Black Dial (62625184)') in the list.
>
> But when accessing through 'print inlist[0]' is possible,i.e it shows
> the e;lement. but the list skips it. .
> Please enlighten me. .
> Thanks.
>
>

Why don't you show us your actual code?  There is no for loop above and 
running the actual code gives "ValueError: 0 is not in list" on the 
first pass through the while loop.

-- 
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence




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