What behavior would you expect?

[Chris Angelico]

On Fri, Feb 20, 2015 at 4:51 PM, Jason Friedman <jsf80238 at gmail.com> wrote:
>> I'd still advise using my_list.sort() rather than sorted(), as you
>> don't need to retain the original.
>>
>
> Hmm.
>
> Trying to figure out what that looks like.
> If I understand correctly, list.sort() returns None.
> What would I return to the caller?

Check its docs: it sorts the list in place. So you return the list,
after you sort it. It's like appending to a list: None is returned and
the list itself is changed.

ChrisA