What interface is a ‘Popen.stdout’ presenting?

[Ben Finney]

I left the Subject field with the wrong question. The immediate answer
is “it presents the ‘file’ interface”. The consequent questions remain:

Ben Finney <ben+python at benfinney.id.au> writes:

>     $ python2
[…]
>     >>> gnupg_stdout = io.TextIOWrapper(gnupg_subprocess.stdout)
>     Traceback (most recent call last):
>       File "<stdin>", line 1, in <module>
>     AttributeError: 'file' object has no attribute 'readable'
>
> I'm trying to write code that, as far as practicable, works unchanged
> on Python 2 and Python 3.
>
> How do I wrap an arbitrary byte stream – already opened, such as a
> ‘Popen.stdout’ attribute – in a text wrapper with a particular
> encoding?

It appears the Python 2 ‘file’ type doesn't implement a “buffer” as
expected by ‘io.TextIOWrapper’.

So how do I get from a Python 2 ‘file’ object, to whatever
‘io.TextIOWrapper’ wants?

-- 
 \     “Nature is trying very hard to make us succeed, but nature does |
  `\       not depend on us. We are not the only experiment.” —Richard |
_o__)                                   Buckminster Fuller, 1978-04-30 |
Ben Finney