Calling a list of functions

[BartC]

On 13/12/2015 17:26, Ganesh Pal wrote:

> Iam on linux and python 2.7  . I have a bunch of functions  which I
> have run sequentially .
> I have put them in a list and Iam calling the functions in the list as
> shown below ,  this works fine for me , please share your
> opinion/views on the same
>
>
> Sample code :
>
> def print1():
>      print "one"
>
> def print2():
>      print "two"
>
> def print3():
>      print "three"
>
> print_test = [print1(),print2(),print3()] //calling the function
>
> for test in range(len(print_test)):
>    try:
>        print_test[test]
>    except AssertionError as exc:
>

 > I have put them in a list and Iam calling the functions in the list as
 > shown below ,  this works fine for me , please share your

That's not quite what the code does, which is to call the three 
functions and put their results into the list (3 Nones I think).

Then you evaluate each element of the list (a None each time).

I had to modify it to the following, which sets up a list of the three 
functions, then calls them in turn using the loop. I don't know what the 
'except' part was supposed to do:

def print1():
     print "one"

def print2():
     print "two"

def print3():
     print "three"

print_test = [print1,print2,print3]	#NOT calling the function

for test in range(len(print_test)):
     try:
     	print_test[test]()              #calling the function
     except AssertionError:
     	pass

The output of the two programs would have been the same I think.

-- 
Bartc