Mock object but also assert method calls?

[Thomas Lehmann]

Am Freitag, 14. August 2015 04:53:56 UTC+2 schrieb Steven D'Aprano:
> On Fri, 14 Aug 2015 07:21 am, Ben Finney wrote:
> 
> >> If find following totally different to the normal API which
> >> is provided by the mock library:
> >>
> >> assert call().test2("hello") in mocked_objects.mock_calls
> > 
> > The 'assert' statement is a crude tool, which knows little about the
> > intent of your assertion.
> 
> I agree with Ben here. Despite the popularity of "nose" (I think it is
> nose?) which uses `assert` for testing, I think that is a gross misuse of
> the statement. It is okay to use assertions this way for quick and dirty ad
> hoc testing, say at the command line, but IMO totally inappropriate for
> anything more formal, like unit testing.
> 
> If for no other reason than the use of `assert` for testing makes it
> impossible to test your code when running with the Python -O (optimize)
> switch.
> 
> For more detail on the uses, and abuses, of `assert` see this:
> 
Of course you do NOT use assert in unit tests but I provided
just test code to show my problem. Of course I take nose and
hamcrest and code coverage ...

Here a complete example of my problem (with comments):


from mock import MagicMock, call, patch

class Bla:
    def test1(self, value):
        pass
    
mocked_object = MagicMock(Bla)
bla = Bla()
bla.test1("hello")
# empty, why?
print(mocked_object.mock_calls)
# does not work: mocked_object.test1.assert_called_with("hello")

with patch("__main__.Bla") as mocked_object:
    bla = Bla()
    bla.test1("hello")
    # not empty!
    print(mocked_object.mock_calls)
    # does also not work: mocked_object.test1.assert_called_with("hello")
    # but this does work:
    assert call().test1("hello") in mocked_object.mock_calls


I don't wanna patch each individual method. Is there no other way?