I am out of trial and error again Lists

[Seymore4Head]

On Fri, 24 Oct 2014 08:05:01 +0100, Mark Lawrence
<breamoreboy at yahoo.co.uk> wrote:

>On 22/10/2014 21:30, Seymore4Head wrote:
>> def nametonumber(name):
>>      lst=[""]
>>      for x,y in enumerate (name):
>>          lst=lst.append(y)
>>      print (lst)
>>      return (lst)
>> a=["1-800-getcharter"]
>> print (nametonumber(a))#18004382427837
>>
>>
>> The syntax for when to use a () and when to use [] still throws me a
>> curve.
>>
>> For now, I am trying to end up with a list that has each character in
>> "a" as a single item.
>>
>> I get:
>> None
>> None
>>
>
>Following on from the numerous responses you've had here, I've no idea 
>if this helps your thought processes but there's only one way for you to 
>find out http://www.greenteapress.com/thinkpython/ :)

I have at least 10 ebooks.  I will get around to reading them soon.
http://i.imgur.com/rpOcKP8.jpg

Thanks