I am out of trial and error again Lists

[Mark Lawrence]

On 22/10/2014 21:30, Seymore4Head wrote:
> def nametonumber(name):
>      lst=[""]
>      for x,y in enumerate (name):
>          lst=lst.append(y)
>      print (lst)
>      return (lst)
> a=["1-800-getcharter"]
> print (nametonumber(a))#18004382427837
>
>
> The syntax for when to use a () and when to use [] still throws me a
> curve.
>
> For now, I am trying to end up with a list that has each character in
> "a" as a single item.
>
> I get:
> None
> None
>

Following on from the numerous responses you've had here, I've no idea 
if this helps your thought processes but there's only one way for you to 
find out http://www.greenteapress.com/thinkpython/ :)

-- 
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence