I am out of trial and error again Lists

Seymore4Head Seymore4Head at Hotmail.invalid
Thu Oct 23 09:53:48 EDT 2014


On Thu, 23 Oct 2014 00:10:28 -0700, Larry Hudson <orgnut at yahoo.com>
wrote:

>On 10/22/2014 03:30 PM, Seymore4Head wrote:
>> On Wed, 22 Oct 2014 16:30:37 -0400, Seymore4Head
>> <Seymore4Head at Hotmail.invalid> wrote:
>>
>> One more question.
>> if y in str(range(10)
>> Why doesn't that work.
>> I commented it out and just did it "long hand"
>>
>> def nametonumber(name):
>>      lst=[]
>>      nx=[]
>>      for x in (name):
>>          lst.append(x)
>>      for y in (lst):
>>          #if y in str(range(10)):
>>          if y in "1234567890":
>>              nx.append(y)
>>          if y in " -()":
>>              nx.append(y)
>>          if y in "abc":
>>              nx.append("2")
>>          if y in "def":
>>              nx.append("3")
>>          if y in "ghi":
>>              nx.append("4")
>>          if y in "jkl":
>>              nx.append("5")
>>          if y in "mno":
>>              nx.append("6")
>>          if y in "pqrs":
>>              nx.append("7")
>>          if y in "tuv":
>>              nx.append("8")
>>          if y in "wxyz":
>>              nx.append("9")
>>      number="".join(str(e) for e in nx)
>>      return (number)
>> a="1-800-getcharter"
>> print (nametonumber(a))#1800 438 2427 837
>> a="1-800-leo laporte"
>> print (nametonumber(a))
>> a="1 800 callaprogrammer"
>> print (nametonumber(a))
>>
>I know you are trying to explore lists here, but I found myself somewhat intrigued with the 
>problem itself, so I wrote a different version.  This version does not use lists but only 
>strings.  I'm just presenting it as-is to let you try to follow the logic, but if you ask, I'll 
>explain it in detail.  It turns your long sequence of if's essentially into a single line -- 
>unfortunately 's' and 'z' have to be handled as special-cases, which turns that single line into 
>a six-line if/elif/else set.  You might consider this line 'tricky', but I'll just say it's just 
>looking at the problem from a different viewpoint.  BTW, this version accepts upper-case as well 
>as lower-case.  isdigit() and isalpha() are standard string methods.
>
>#------  Code  ----------
>def name2number(name):
>     nstr = ''    #  Phone-number string to return
>     codes = 'abcdefghijklmnopqrtuvwxy'  #  Note missing s and z
>
>     for ch in name:
>         if ch in " -()":
>             nstr += ch
>         elif ch.isdigit():
>             nstr += ch
>         elif ch.isalpha():
>             ch = ch.lower()
>             #   S and Z are special cases
>             if ch == 's':
>                 nstr += '7'
>             elif ch == 'z':
>                 nstr += '9'
>             else:
>                 nstr += str(codes.index(ch) // 3 + 2)
>     return nstr
>#-------  End of Code  ---------
>
>A possible variation would be to make nstr a list instead of a string, and use .append() instead 
>of the +=, and finally return the string by using join() on the list.  Also, the if and first 
>elif in the for could be combined:  if ch in " -()" or ch.isdigit():
>
>      -=- Larry -=-
Sure I will have a look at it.  I am always open on better ways to do
something.
Thanks



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