Matplotlib: getting a figure to show without plt.show()
Peter Pearson
pkpearson at nowhere.invalid
Wed Oct 22 00:57:23 EDT 2014
I'm using Matplotlib to present a "control" window with clickable
buttons, and to plot things in another window when you click buttons,
in the style of the code below. I'm ashamed of the stinky way I
use "first" to call plt.show the first time data are plotted but then
to call fig.canvas.draw for subsequent data plots. Can someone tell
me the right way?
If I call plt.show every time, then after about 40 plots I get
"RuntimeError: maximum recursion depth exceeded while calling a Python
object", which makes sense because I'm getting one layer deeper in
callbacks with every plot (plt.show doesn't return). But if I call
fig.canvas.draw every time, the window for the data plot never appears
on my screen.
Thanks for any suggestions.
##############################
import matplotlib.pyplot as plt
from matplotlib.widgets import Button
def callback(event):
global n, first
fig = plt.figure(2)
fig.clear()
plt.plot([0,1],[0,n])
n += 1 # (Pretending something changes from one plot to the next.)
if first:
first = False
plt.show()
else:
fig.canvas.draw()
global n, first
n = 0
first = True
fig = plt.figure(1)
quit_button = Button(plt.axes([.1,.3,.4,.2]), "Quit")
quit_button.on_clicked(lambda x: plt.close("all"))
plot_button = Button(plt.axes([.1,.1,.4,.2]), "Plot")
plot_button.on_clicked(callback)
plt.show()
##############################
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