Regular Expression for the special character "|" pipe

[Mark Lawrence]

On 27/05/2014 12:39, Aman Kashyap wrote:
> On Tuesday, 27 May 2014 16:59:38 UTC+5:30, Daniel  wrote:
>> What about skipping the re and try this:
>>
>>
>>
>> 'start=|ID=ter54rt543d|SID=ter54rt543d|end=|'.split('|')[1][3:]
>>
>>
>>
>> On 27.05.2014 14:09, Vlastimil Brom wrote:
>>
>>> 2014-05-27 12:59 GMT+02:00 Aman Kashyap <amankashyap1223 at gmail.com>:
>>
>>>> I would like to create a regular expression in which i can match the "|" special character too.
>>
>>>>
>>
>>>> e.g.
>>
>>>>
>>
>>>> start=|ID=ter54rt543d|SID=ter54rt543d|end=|
>>
>>>>
>>
>>>> I want to only |ID=ter54rt543d| from the above string but i am unable to write the  pattern match containing "|" pipe too.
>>
>>>>
>>
>>>> By default python treat "|" as an OR operator.
>>
>>>>
>>
>>>> But in my case I want to use to as a part of search string.
>>
>>>> --
>>
>>> Hi,
>>
>>> you can just escpape the pipe with backlash like any other metacharacter:
>>
>>>
>>
>>> r"start=\|ID=ter54rt543d"
>>
>>>
>>
>>> be sure to use the raw string notation r"...", or you can double all
>>
>>> backslashes in the string.
>>
>>>
>>
>>> hth,
>>
>>>      vbr
>
> Thanks for the response.
>
> I got the answer finally.
>
> This is the regular expression to be used:\\|ID=[a-z]*[0-9]*[a-z]*[0-9]*[a-z]*\\|
>

I'm pleased to see that you have answers.  In return would you please 
use the mailing list 
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-- 
My fellow Pythonistas, ask not what our language can do for you, ask 
what you can do for our language.

Mark Lawrence

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