datetime

Peter Otten __peter__ at web.de
Wed Mar 26 17:33:32 EDT 2014


Victor Engle wrote:

> I want to keep a collection of data organized by collection date and I'll
> use datetime like this...
> 
>>>> datetime.date.today()
> 
> datetime.date(2014, 3, 26)
> 
> 
> I'll format the date and create directories like /mydata/yyyy-mm-dd
> 
> 
> When I create a directory for today, I need to know the directory name for
> yesterday and tomorrow. In perl I could get seconds since the epoch using
> time and then add or subtract from that number for tomorrow or yesterday
> and feed that into localtime to get the date string.
> 
> 
> It would be convenient if  datetime.date.today() accepted an argument as
> an offset from today, like datetime.date.today(-1). Is there an easy way
> to do this with datetime?

>>> import datetime
>>> ONE_DAY = datetime.timedelta(days=1)
>>> today = datetime.date.today()
>>> today
datetime.date(2014, 3, 26)
>>> today - ONE_DAY
datetime.date(2014, 3, 25)
>>> today + ONE_DAY
datetime.date(2014, 3, 27)





More information about the Python-list mailing list