help with for loop----python 2.7.2

[Ben Finney]

teddybubu at gmail.com writes:

> I am trying to get all the element data from the rss below.

[…]

> from bs4 import BeautifulSoup 
>
> soup = BeautifulSoup(urlopen('http://bl.ocks.org/mbostock.rss'))

RSS is not HTML; so BeautifulSoup is not a good tool to use for parsing
RSS.

Instead, you will do better if you use one of the libraries already
written for RSS parsing <URL:https://wiki.python.org/moin/RssLibraries>.

-- 
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Ben Finney