Modifying the default argument of function
Chris Angelico
rosuav at gmail.com
Tue Jan 21 14:19:12 EST 2014
On Wed, Jan 22, 2014 at 6:11 AM, Mû <mu-- at melix.net> wrote:
> The function acts as if there were a global variable x, but the call of x
> results in an error (undefined variable). I don't understand why the
> successive calls of f() don't return the same value: indeed, I thought that
> [2,3] was the default argument of the function f, thus I expected the three
> calls of f() to be exactly equivalent.
In a sense, there is. The default for the argument is simply an object
like any other, and it's stored in one place.
For cases where you want a mutable default that is "reset" every time,
the most common idiom is this:
def f(x=None):
if x is None: x=[2,3]
x.append(1)
return x
That will create a new list every time, with the same initial contents.
ChrisA
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