Simple % question

[Scott W Dunning]

On Feb 11, 2014, at 6:51 PM, Christopher Welborn <cjwelborn at live.com> wrote:

> I think because 1 is evenly divisible by 10 exactly 0 times with a 1
> remainder. I mean int(1 / 10) == 0, with a 1 remainder.
> The same is true for all numbers leading up to 10.
> 
Actually I think I get it now.  I think I was not really looking at it as 1/10 more like the other way around.