Sorting dictionary by datetime value
Peter Otten
__peter__ at web.de
Sat Feb 8 03:27:20 EST 2014
Frank Millman wrote:
>
> "Chris Angelico" <rosuav at gmail.com> wrote in message
> news:CAPTjJmqDusdFC1eLbU6LF5-up__LAE-63ii0UUvAGGNem9U4+w at mail.gmail.com...
>> On Sat, Feb 8, 2014 at 6:06 PM, Igor Korot <ikorot01 at gmail.com> wrote:
>>>>>> sorted(a.items(), key=a.get)
>>> [('1', datetime.datetime(2012, 12, 28, 12, 15, 30, 100)), ('3',
>>> datetime.datetim
>>> e(2012, 12, 28, 12, 16, 44, 100)), ('2', datetime.datetime(2012, 12, 28,
>>> 12, 17,
>>> 29, 100))]
>
> That seemed like a neat trick, so I thought I would try to understand it a
> bit better in case I could use it some day.
>
> I am using python3. I don't know if that makes a difference, but I cannot
> get it to work.
>
>>>> d = {1: 'abc', 2: 'xyz', 3: 'pqr'}
>>>> sorted(d.items(), key=d.get)
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> TypeError: unorderable types: NoneType() < NoneType()
>>>>
>
> I know that python3 is stricter regarding ordering of non-comparable
> types, but I don't see where None is coming from.
>
> I have python 2.7.3 on another machine. Here are the results -
>
>>>> d = {1: 'abc', 2: 'xyz', 3: 'pqr'}
>>>> sorted(d.items(), key=d.get)
> [(1, 'abc'), (2, 'xyz'), (3, 'pqr')]
>
> It did not crash, but it did not sort.
>
> Then I changed the keys to strings, to match Igor's example -
>
>>>> d = {'1': 'abc', '2': 'xyz', '3': 'pqr'}
>>>> sorted(d.items(), key=d.get)
> [('1', 'abc'), ('3', 'pqr'), ('2', 'xyz')]
>
> It works - now I am even more confused.
>
> Any hints will be appreciated.
Chris has already explained it. Here you can watch the key calculation at
work:
>>> d = {'1': 'abc', '2': 'xyz', '3': 'pqr'}
>>> def sortkey(value):
... key = d.get(value)
... print "value:", value, "sort-key:", key
... return key
...
>>> sorted(d.items(), key=sortkey)
value: ('1', 'abc') sort-key: None
value: ('3', 'pqr') sort-key: None
value: ('2', 'xyz') sort-key: None
[('1', 'abc'), ('3', 'pqr'), ('2', 'xyz')]
Can you change the dict to make d.get return non-None values?
The OP was probably trying to mimic sorted(d, key=d.get) which sorts the
dict keys by the associated dict values:
>>> sorted(d, key=sortkey)
value: 1 sort-key: abc
value: 3 sort-key: pqr
value: 2 sort-key: xyz
['1', '3', '2']
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