[newbie] copying identical list for a function argument
Gary Herron
gary.herron at islandtraining.com
Mon Feb 3 17:06:16 EST 2014
On 02/03/2014 01:36 PM, Jean Dupont wrote:
> I have a list like this:
> [1,2,3]
>
> The argument of my function should be a repeated version e.g.
> [1,2,3],[1,2,3],[1,2,3],[1,2,3] (could be a different number of times repeated also)
That's not very clear. You say "The" argument (singular; meaning 1) but
then show what seems to be four arguments. Can you show us the function
you mention.
A number of things come to mind:
>>> 4*[[1,2,3]]
[[1, 2, 3], [1, 2, 3], [1, 2, 3], [1, 2, 3]]
so fn(n*[[1,2,3]]) might do for a single parameter function
def fn(L):
...
On the other hand expanding a sequence into individual parameters:
fn(*(4*[[1,2,3]])) # note extra * preceding the arg
willl be a valid call for
def fn(a,b,c,d):
...
I'm sure other interpretations of your question are possible.
Gary Herron
>
> what is the prefered method to realize this in Python?
>
> any help would be really appreciated
>
> kind regards,
> jean
>
More information about the Python-list
mailing list