Python console rejects an object reference, having made an object with that reference as its name in previous line

[Chris Roy-Smith]

On 15/12/14 10:21, Simon Evans wrote:
> Dear Jussi, and Billy
> I have changed the input in accordance with your advice, re:
> ------------------------------------------------------------------------------
> Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (Intel)] on win

here the user is using python 2.7.6


> 32
> Type "help", "copyright", "credits" or "license" for more information.
>>>> from bs4 import BeautifulSoup
>>>> with open("ecologicalpyramid.html","r") as ecological_pyramid:
> ...      soup = next(ecological_pyramid,"lxml")
> ...      producer_entries = soup.find("ul")
> ...      print(producer_entries.li.div.string)
> ... print(producer_entries.li.div.string)
>    File "<stdin>", line 5
>      print(producer_entries.li.div.string)
>          ^

and here he uses a python 3.x print syntax which triggers the following 
error message

> SyntaxError: invalid syntax
>>>> print (producer_entries.li.div.string)
> Traceback (most recent call last):
>    File "<stdin>", line 1, in <module>
> NameError: name 'producer_entries' is not defined
>>>> from bs4 import BeautifulSoup
>>>> with open("ecologicalpyramid.html","r") as ecological_pyramid:
> ...      soup = next(ecological_pyramid,"lxml")
> ...      producer_entries = soup.find("ul")
> ...      print(producer_entries.li.div.string)
> ...
> ----------------------------------------------------------------------------
> As no doubt you can see, the last line, indented as it is, does not provide the output that the book's text says it will return - ie the word 'plants'
> If I do not indent it, it returns an 'invalid syntax error' stating that 'producer_entries' is not defined. Though code in the previous line is meant to do just that - isn't it ?
>