Python console rejects an object reference, having made an object with that reference as its name in previous line

[Simon Evans]

I had another attempt at inputting the code perhaps with the right indentation, I still get an error return, but not one that indicates that the code has not been read, as you suggested. re:- 
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Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (Intel)] on win
32
Type "help", "copyright", "credits" or "license" for more information.
>>> from bs4 import BeautifulSoup
>>> with open("ecologicalpyramid.html","r") as ecological_pyramid:
...      soup = BeautifulSoup(ecological_pyramid,"lxml")
... producer_entries = soup.find("ul")
  File "<stdin>", line 3
    producer_entries = soup.find("ul")
                   ^
SyntaxError: invalid syntax
>>>  from bs4 import BeautifulSoup
  File "<stdin>", line 1
    from bs4 import BeautifulSoup
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If, as you suggest I left a free line after the "with open( etc" line, console returns an error, if I leave a free line after the "soup = etc" line which comes after, again I get an error return, my only point is that with the above input, console return does not seem to infer that soup has not been defined. You recommend that I put all the code into a file then run it - how do I do that ? I am new to Python, as you might have gathered. 
Thank you for your help.
Yours Simon