How to detect that a function argument is the default one
Jean-Michel Pichavant
jeanmichel at sequans.com
Wed Dec 10 11:10:03 EST 2014
----- Original Message -----
> From: "ast" <nomail at invalid.com>
> I have the idea to write:
>
> def __init__(center=(0,0), radius=10, mass=None)):
>
> if mass == None:
> self.mass = radius**2
> else:
> self.mass = mass
>
> but maybe Python provides something clever.
>
> Thx
If you like one-liners,
def __init__(self, center=(0,0), radius=10, mass=None):
self.center = center
self.radius = radius
self.mass = (mass is None and radius**2) or mass
But there's an issue with that solution: self.mass being computed during the instance initialization, what if radius is changing ?
c1 = Circle((0,0), 10, None)
print c1.mass
20
c1.radius = 20
print c1.mass
20 # that is unexpected
Everytime an attribute is computed from another attribute, it should ring a python bell : property
def __init__(self, center, radius, mass):
self.center = center
self.radius = radius
self._mass = mass
@property
def mass(self):
return self._mass if self._mass is not None else self.radius*2
c1 = Circle((0,0), 10, None)
print c1.mass
20
c1.radius = 20
print c1.mass
40
JM
Note : what is the mass of a circle ?
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