dict turn to list unexpected at runtime???
telnetgmike at gmail.com
telnetgmike at gmail.com
Fri Dec 5 02:31:40 EST 2014
On Friday, December 5, 2014 3:20:14 PM UTC+8, Cameron Simpson wrote:
> On 05Dec2014 15:01, telnetgmike at gmail.com <telnetgmike at gmail.com> wrote:
> >Why the following code gives me errors??? And why the print statement run 2 times? I'll be appreciated your helps, thanks,
> >addrnum_dict = {'a':1,'b':2}
> >def orderaddrtimes():
> > global addrnum_dict
> > print type(addrnum_dict)
> >
> > addrnum_dict = sorted(addrnum_dict.iteritems(), key=lambda d:d[1], reverse = True)
>
> Because of the line above. The return value of "sorted()" is a list. You assign
> that list to "addrnum_dict". That name now refers to the list from "sorted()".
>
> Because you call the orderaddrtimes() function twice, the second time you call
> it "addrnum_dict" is the list from the first call. Not a dict.
>
> You would be best to not assign the result of "sorte()" to "addrnum_dict".
> Assign it to something else.
>
> > #addrnum_dict = OrderedDict(sorted(addrnum_dict.items(), key=lambda t: t[0]))
> >if __name__ == '__main__':
> > kinds = ["a","b"]
> > for tmp_kind in kinds:
> > orderaddrtimes()
> >
> >######################
> >errors:
> >python aaa.py
> ><type 'dict'>
> ><type 'list'>
> >Traceback (most recent call last):
> > File "aaa.py", line 16, in <module>
> > orderaddrtimes()
> > File "aaa.py", line 11, in orderaddrtimes
> > addrnum_dict = sorted(addrnum_dict.iteritems(), key=lambda d:d[1], reverse = True)
> >AttributeError: 'list' object has no attribute 'iteritems'
>
> Thank you for including the complete error output. This is very helpful, and
> often essential.
>
> Cheers,
> Cameron Simpson <cs at zip.com.au>
>
> Who are all you people and why are you in my computer? - Kibo
Thanks for your help!
I admit I have poor experience on python, and I careless also.
Thanks!
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