Scoping rules for class definitions
Ian Kelly
ian.g.kelly at gmail.com
Fri Apr 4 14:55:07 EDT 2014
On Fri, Apr 4, 2014 at 12:37 PM, Rotwang <sg552 at hotmail.co.uk> wrote:
> Hi all. I thought I had a pretty good grasp of Python's scoping rules, but
> today I noticed something that I don't understand. Can anyone explain to me
> why this happens?
>
>>>> x = 'global'
>>>> def f1():
> x = 'local'
> class C:
> y = x
> return C.y
>
>>>> def f2():
> x = 'local'
> class C:
> x = x
> return C.x
>
>>>> f1()
> 'local'
>>>> f2()
> 'global'
Start by comparing the disassembly of the two class bodies:
>>> dis.dis(f1.__code__.co_consts[2])
3 0 LOAD_NAME 0 (__name__)
3 STORE_NAME 1 (__module__)
6 LOAD_CONST 0 ('f1.<locals>.C')
9 STORE_NAME 2 (__qualname__)
4 12 LOAD_CLASSDEREF 0 (x)
15 STORE_NAME 3 (y)
18 LOAD_CONST 1 (None)
21 RETURN_VALUE
>>> dis.dis(f2.__code__.co_consts[2])
3 0 LOAD_NAME 0 (__name__)
3 STORE_NAME 1 (__module__)
6 LOAD_CONST 0 ('f2.<locals>.C')
9 STORE_NAME 2 (__qualname__)
4 12 LOAD_NAME 3 (x)
15 STORE_NAME 3 (x)
18 LOAD_CONST 1 (None)
21 RETURN_VALUE
The only significant difference is that the first uses
LOAD_CLASSDEREF, which I guess is the class version of LOAD_DEREF for
loading values from closures, at line 4 whereas the second uses
LOAD_NAME. So the first one knows about the x in the nonlocal scope,
whereas the second does not and just loads the global (since x doesn't
yet exist in the locals dict).
Now why doesn't the second version also use LOAD_CLASSDEREF? My guess
is because it's the name of a local; if it were referenced a second
time in the class then the second LOAD_CLASSDEREF would again get the
x from the nonlocal scope, which would be incorrect.
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