Compact way to assign values by slicing list in Python

[Marco Buttu]

On 04/02/2014 01:17 AM, Mark Lawrence wrote:
> Came across this
> http://stackoverflow.com/questions/22756632/compact-way-to-assign-values-by-slicing-list-in-python?newsletter=1&nlcode=245176|202f
> - just curious what you guys and gals thought of the answers.

I prefere this one:

bar = ['a','b','c','x','y','z']
v1, _, _, v2, v3, _ = bar

I also like the solution with itemgetter:

v1, v2, v3 = itemgetter(0, 3, 4)(bar)

but I think it is less readable than the previous one

-- 
Marco Buttu