Code style query: multiple assignments in if/elif tree

David Hutto dwightdhutto at gmail.com
Tue Apr 1 03:34:03 EDT 2014


You would be assuming a quantum leap type theory, that the object has no
Vo->V1, it just adjusts to the constant immediately, instead of what I
would call the quantum leap,without other 'theories' involved, that it has
a classical physics type movement in which it can accelerate from a resting
position, to a velocity, and then regain orbit:

http://wiki.answers.com/Q/What_is_a_quantum_leap



On Tue, Apr 1, 2014 at 3:21 AM, David Hutto <dwightdhutto at gmail.com> wrote:

> u is the initial velocity from a starting/resting point, not a static
> speed at that point, and begins to accelerate,
> over a particular timeframe, in which it's momentum is not stopped by
> friction on which the rails/environment it travels upon has, or the similar
> properties the object might have during acceleration in relation to the
> environment it travels within.
>
> So the object has a starting point at which there is no equal, or opposing
> force, as it begins to accelerate from a resting position(Newton: an object
> will remain in motion, until acted upon  by an equal or opposite force, and
> in this case the motion is propulsion of the object, or the newtons of
> propulsion, until it is moving at the exact speed of the propulsion applied
> to the object->Vo-V1, with 0 friction/viscosity during this timeframe).
>
> The difference in our opinions, seems to be that there is an initial
> resting state, and not at an already accelerated motion that has reached
> it's maximum capacity.
>
>
> So there is a dynamic in my mind's eye, where the object is at a "resting"
> point initially, and either the environment, or the object can maneuver
> their own viscosity in relation to the other.
>
>
> On Tue, Apr 1, 2014 at 2:39 AM, Ian Kelly <ian.g.kelly at gmail.com> wrote:
>
>> On Tue, Apr 1, 2014 at 12:24 AM, David Hutto <dwightdhutto at gmail.com>
>> wrote:
>> >>
>> >> >> (1) v = u + at
>> >> >> (2) s = 1/2(u + v)t
>> >> >> (3) s = ut + 1/2(at^2)
>> >> >> (4) v^2 = u^2 + 2as
>> >> >>
>> >> >> Only (1) and (3) are needed.
>> >> >
>> >> > Okay, what's u here? Heh.
>> >>
>> >> u is the initial velocity; v is the velocity after accelerating at a
>> for
>> >> time t.
>> >
>> >
>> > This assumes that the viscosity is in a state of superfluidity, and in a
>> > perfect state between itself, and it's traveling environment.
>>
>> I fail to see how this is relevant.  I would assume that the amount of
>> friction is already modeled in the acceleration constants; if it were
>> zero then the brakes would be nonfunctional and the train would not be
>> able to accelerate or decelerate at all.  In any case, a change in
>> friction simply works out to a change in acceleration.  The equations
>> above still hold true.
>> --
>> https://mail.python.org/mailman/listinfo/python-list
>>
>
>
>
> --
> Best Regards,
> David Hutto
> *CEO:* *http://www.hitwebdevelopment.com
> <http://www.hitwebdevelopment.com>*
>



-- 
Best Regards,
David Hutto
*CEO:* *http://www.hitwebdevelopment.com <http://www.hitwebdevelopment.com>*
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