compare two list of dictionaries

MRAB python at mrabarnett.plus.com
Fri Oct 4 12:41:36 EDT 2013


On 04/10/2013 03:29, Mohan L wrote:
[snip]
>
> output1=[
> {'count': 3 , 'ip': 'xxx.xx.xxx.1'},
> {'count': 4, 'ip': 'xxx.xx.xxx.2'},
> {'count': 8, 'ip': 'xxx.xx.xxx.3'},
> {'count': 10, 'ip': 'xxx.xx.xxx.4'},
> {'count': 212, 'ip': 'hostname1'},
> {'count': 27, 'ip': 'hostname2'},
> {'count': 513, 'ip': 'hostname3'},
> {'count': 98, 'ip': 'hostname4'},
> {'count': 1, 'ip': 'hostname10'},
> {'count': 2, 'ip': 'hostname8'},
> {'count': 3, 'ip': 'xxx.xx.xxx.11'},
> {'count': 90, 'ip': 'xxx.xx.xxx.12'},
> {'count': 12, 'ip': 'xxx.xx.xxx.13'},
> {'count': 21, 'ip': 'xxx.xx.xxx.14'},
> {'count': 54, 'ip': 'xxx.xx.xxx.15'},
> {'count': 34, 'ip': 'xxx.xx.xxx.16'},
> {'count': 11, 'ip': 'xxx.xx.xxx.17'},
> {'count': 2, 'ip': 'xxx.xx.xxx.18'},
> {'count': 19, 'ip': 'xxx.xx.xxx.19'},
> {'count': 21, 'ip': 'xxx.xx.xxx.20'},
> {'count': 25, 'ip': 'xxx.xx.xxx.21'},
> {'count': 31, 'ip': 'xxx.xx.xxx.22'},
> {'count': 43, 'ip': 'xxx.xx.xxx.23'},
> {'count': 46, 'ip': 'xxx.xx.xxx.24'},
> {'count': 80, 'ip': 'xxx.xx.xxx.25'},
> {'count': 91, 'ip': 'xxx.xx.xxx.26'},
> {'count': 90, 'ip': 'xxx.xx.xxx.27'},
> {'count': 10, 'ip': 'xxx.xx.xxx.28'},
> {'count': 3, 'ip': 'xxx.xx.xxx.29'}]
>
>
>
> output2=(('INNCHN01','xxx.xx.xxx.11'),
> ('HYDRHC02', 'xxx.xx.xxx.12'),
> ('INNCHN03','xxx.xx.xxx.13'),
> ('MUMRHC01','xxx.xx.xxx.14'),
> ('n/a','xxx.xx.xxx.15'),
> ('INNCHN05','xxx.xx.xxx.16'),
> ('hostname1','n/a'),
> ('hostname2','n/a'),
> ('hostname10',''),
> ('hostname8',''),
> ('hostname200','xxx.xx.xxx.200'),
> ('hostname300','xxx.xx.xxx.400'),
> )
>
> ## 1).
> ## Create a dict from output1 in which the key is the ip and the value
> is the count.
> mongodb_data={}
> for doc in output1:
>          mongodb_data.update({doc['ip']:doc['count']})
>
A simpler way is:

mongodb_data = {}
for doc in output1:
     mongodb_data[doc['ip']] = doc['count']

> ## Create a set from output2 containing all the hostnames and ip_addrs.
> all_hostname_ip_set=set(list(sum(output2, ())))
>
> ## Get the intersection of the keys of the dict with the set.
> key_set=set(mongodb_data.keys())
> int_keys=key_set & all_hostname_ip_set
> # Print the entries of the dict for each member of the intersection.
> print "-------------------intersection-----------------------------"
> for key in int_keys:
>          print key,mongodb_data[key]
>
> ## 2).
> ## Get the difference between the keys of the dict and the intersection.
> deff_keys=key_set - all_hostname_ip_set
> ## Print the entries of the dict for each member of the difference.
> print "-------------------difference-------------------------------"
> for key in deff_keys:
>      print key,mongodb_data[key]
>
>
> $ ./demo.py
>
> -------------------intersection-----------------------------
> xxx.xx.xxx.11 3
> xxx.xx.xxx.12 90
> xxx.xx.xxx.13 12
> xxx.xx.xxx.14 21
> xxx.xx.xxx.15 54
> xxx.xx.xxx.16 34
> hostname2 27
> hostname1 212
> hostname10 1
> hostname8 2
> -------------------difference-------------------------------
> xxx.xx.xxx.29 3
> xxx.xx.xxx.28 10
> xxx.xx.xxx.17 11
> xxx.xx.xxx.18 2
> xxx.xx.xxx.19 19
> xxx.xx.xxx.23 43
> xxx.xx.xxx.22 31
> xxx.xx.xxx.25 80
> xxx.xx.xxx.24 46
> xxx.xx.xxx.27 90
> xxx.xx.xxx.26 91
> xxx.xx.xxx.2 4
> xxx.xx.xxx.21 25
> hostname3 513
> hostname4 98
> xxx.xx.xxx.4 10
> xxx.xx.xxx.20 21
> xxx.xx.xxx.1 3
> xxx.xx.xxx.3 8
>
>
>
>         3). Ip address with is there only in output2 dictionary.
>
>         xxx.xx.xxx.200
>         xxx.xx.xxx.400
>
>     1. Create a set from output2 containing all the ip_addrs
>
>
>     2. Get the difference between the set and the keys of the dict created
>     from output1.
>
>
> I have one problem here.  I want to compare the output2 (hostname or ip
> address) with output1 'ip' values (i.e., either hostname or ip address
> of output2 does not matching the ip dict key in output1  then I want to
> print either hostname or ip address from output2).
>
You already have the output1 'ip' values (the keys of mongodb_data) and
the entries of output2 (all_hostname_ip_set). Just find the set
difference.




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