parsing RSS XML feed for item value

xDog Walker thudfoo at gmail.com
Wed Nov 20 11:17:31 EST 2013


On Wednesday 2013 November 20 05:44, Larry Wilson wrote:
> {'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': u'29.6', 'rain':
> u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': u'22.2',
> 'winddirection': u'SSW'}
Python 2.7.2 (default, Oct 10 2011, 10:47:36)
[GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> w_current = {'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': 
u'29.6', 'rain': u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': 
u'22.2', 'winddirection': u'SSW'}
>>> for label, value in w_current.iteritems():
...     print label, value
...
pressure 0.0
windspeed 22.2
temperature 20.3
dewpoint 18.6
windgusts 29.6
winddirection SSW
rain 0.6
humidity 90
>>>         

-- 
Yonder nor sorghum stenches shut ladle gulls stopper torque wet 
strainers.




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