Implementing #define macros similar to C on python

[JL]

Thanks! This is the answer which I am seeking. However, I am not able to get the following line to work. I am using python 2.7.5

debug_print = print

Can we assign a function into a variable in this manner?

On Friday, November 15, 2013 11:49:52 AM UTC+8, Chris Angelico wrote:
> On Fri, Nov 15, 2013 at 1:29 PM, JL <lightaiyee at gmail.com> wrote:
> 
> > One of my favorite tools in C/C++ language is the preprocessor macros.
> 
> >
> 
> > One example is switching certain print messages for debugging use only
> 
> >
> 
> > #ifdef DEBUG_ENABLE
> 
> > DEBUG_PRINT   print
> 
> > #else
> 
> > DEBUG_PRINT
> 
> >
> 
> > Is it possible to implement something similar in python? Thank you.
> 
> 
> 
> There are usually other ways to do things. For instance, you can
> 
> define a function to either do something or do nothing:
> 
> 
> 
> if debug_mode:
> 
>     debug_print = print
> 
> else:
> 
>     debug_print = lambda: None
> 
> 
> 
> debug_print("This won't be shown unless we're in debug mode!")
> 
> 
> 
> But as Dave says, you could write a preprocessor if you need one.
> 
> 
> 
> ChrisA