Getting globals of the caller, not the defining module
sg552 at hotmail.co.uk
sg552 at hotmail.co.uk
Mon Nov 11 07:02:41 EST 2013
(Sorry for posting through GG, I'm at work.)
On Monday, November 11, 2013 11:25:42 AM UTC, Steven D'Aprano wrote:
> Suppose I have a function that needs access to globals:
>
> # module A.py
> def spam():
> g = globals() # this gets globals from A
> introspect(g)
>
> As written, spam() only sees its own globals, i.e. those of the module in
> which spam is defined. But I want spam to see the globals of the caller.
>
> # module B
> import A
> A.spam() # I want spam to see globals from B
>
> I can have the caller explicitly pass the globals itself:
>
> def spam(globs=None):
> if globs is None:
> globs = globals()
> introspect(globs)
>
> But since spam is supposed to introspect as much information as possible,
> I don't really want to do that. What (if anything) are my other options?
How about this?
# module A.py
import inspect
def spam():
return inspect.stack()[1][0].f_globals
# module B.py
import A
print(A.spam() is globals()) # prints True
def f():
return A.spam()
# module C.py
import B
print(B.f() is vars(B)) # prints True
I don't really know what I'm doing but I guess it won't work in alternative implementations of Python.
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