Printing appropriately based on values retrieved
Nick the Gr33k
nikos.gr33k at gmail.com
Sat Nov 2 15:25:34 EDT 2013
Στις 2/11/2013 8:25 μμ, ο/η Nick the Gr33k έγραψε:
> for row in newdata:
> (host, refs, city, useros, browser, visits, hits, downloads) = row
>
> if downloads != 'Δεν έχει κατεβάσει ταινία':
> print( '<td><select>' )
> for n, download in enumerate( downloads ):
> if n == 0:
> op_selected = 'selected'
> else:
> op_selected = ''
> print( '<option %s> %s </option>' % (op_selected, download) )
> print( '</select></td>' )
> else:
> print( '<td><center><b><font color=white> 'No downloads yet'
> </td>' )
>
>
> The above code is supposed to print a select menu in case it has found
> tha user has downloaded files from my website and if he didn't to just
> print a string 'No downloads yet'.
>
> Unfortunately as i have it, it prints 'No downloads yet' inside a select
> menu giving the impression that the 'No downloads yet' was actually a file.
>
> how should i write it to have the result i want it to be?
--
if downloads != 'Δεν έχει κατεβάσει ακόμη ταινία!':
print( '<td><select>' )
for n, download in enumerate( downloads ):
if n == 0:
op_selected = 'selected'
else:
op_selected = ''
print( '<option %s> %s </option>' % (op_selected, download) )
print( '</select></td>' )
times = times + 1
if times == 0:
print( '<td><center><b><font color=white> Δεν έχει κατεβάσει ακόμη
ταινία! </td>' )
I just tried this this didn't work either :(
Please someone t
More information about the Python-list
mailing list